In graphical solutions of linear inequalities, solution can be di… - Vidyadip

MCQ

In graphical solutions of linear inequalities, solution can be divided into.

A
One subset
✓
Two subsets
C
Three subsets
D
Four subsets

✓

Answer

Correct option: B.

Two subsets

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear Programming→Linear Programming — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

Which of the following is the general solution of $\frac{d^2 y}{d x^2}-2 \frac{d y}{d x}+y=0 ?$

If $\left| {\,\begin{array}{*{20}{c}}a&b&{a + b}\\b&c&{b + c}\\{a + b}&{b + c}&0\end{array}\,} \right| = 0$; then $a,b,c$ are in

The integrating factor of the differential equation $\frac{{dy}}{{dx}} = y\tan x - {y^2}\sec x,$is

$r \times a = b \times a;\,\,r \times b = a \times b;\,\,a \ne 0;\,\,b \ne 0;\,\,a \ne \lambda b,\,\,$ $a $ is not perpendicular to $ b,$ then $r = $

Choose the correct answers from the given four options:
If $\text{f(x)}=\begin{cases}\text{mx}+1,&\text{if x}\leq\frac{\pi}{2}\\\sin\text{x}+\text{n},&\text{if x}>\frac{\pi}{2}\end{cases},$ is continuous at $\text{x}=\frac{\pi}{2},$ then:

A biased die is tossed and the respective probabilities for various faces to turn up are given below

$Face:$	$1$	$2$	$3$	$4$	$5$	$6$
$P(F)$	$0.1$	$0.24$	$0.19$	$0.18$	$0.15$	$0.14$

If an even face has turned up, then the probability that it is face $2$ or face $4$, is

The domain of $f(x) = \frac{1}{{\sqrt {{{\log }_{\frac{\pi }{4}}}({{\sin }^{ - 1}}x) - 1} }}$,is

The function $\text{f}:[0,\infty)\rightarrow\ \text{R}$ given by $\text{f(x)}=\frac{\text{x}}{\text{x}+1}$ is:

If $A=\left[\begin{array}{ccc}-2 & 0 & 0 \\ 0 & -2 & 0 \\ 0 & 0 & -2\end{array}\right]$, then the value of $|\operatorname{adj} A|$ is

The volume of the tetrahedron, whose vertices are given by the vectors $ - i + j + k,\,\,i - j + k$ and $i + j - k$ with reference to the fourth vertex as origin, is