MCQ
In how many ways can 12 people be divided into 3 groups where 4 persons must be there in each group?
  • A
    $\text{None of these}$
  • B
    $\frac{12!}{(4!)^3}$
  • C
    $\text{Insufficient data}$
  • $\frac{12!}{3!\times(4!)^3}$

Answer

Correct option: D.
$\frac{12!}{3!\times(4!)^3}$
Number of ways in which
$\text{m}\times\text{n"}>$
$\text{m}\times\text{n}$ distinct things can be divided equally into n
$\text{n"}>$ groups
$=\frac{(\text{mn})!}{\text{n}!\times(\text{m}!)\text{n}}$
Given, $12(3\times4)$ people needs to be divided into 3 groups where 4 persons must be there in each group.
So, the required number of ways $=\frac{({12})!}{{3}!\times(4!)\text{n}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free