MCQ
In how many ways can 12 people be divided into 3 groups where 4 persons must be there in each group?
  • A
    $\text{None of these}$
  • B
    $\frac{12!}{(4!)^3}$
  • C
    $\text{Insufficient data}$
  • D
    $\frac{12!}{3!\times(4!)^3}$

Answer

  1. $\frac{12!}{3!\times(4!)^3}$

Solution:

Number of ways in which

$\text{m}\times\text{n"}>$

$\text{m}\times\text{n}$ distinct things can be divided equally into n

$\text{n"}>$ groups

$=\frac{(\text{mn})!}{\text{n}!\times(\text{m}!)\text{n}}$

Given, $12(3\times4)$ people needs to be divided into 3 groups where 4 persons must be there in each group.

So, the required number of ways $=\frac{({12})!}{{3}!\times(4!)\text{n}}$

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