Question
In how many ways can five children stand in a queue?

Answer

The total number of ways = Number of arrangements of 5 things, taken all at a time $=^5\text{P}_5$
$=\frac{5!}{(5-5)!}$
$=\frac{5\times4\times3\times2\times1}{0!}\ [\because 0!=1]$
$=120$
Hence, the total numbar of ways in which children stand in a queue is 120.

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