MCQ
In ${K_4}Fe{\left( {CN} \right)_6},$ $Fe$ is in the form of
- AAn atom
- BAn ion
- CCationic complex
- ✓Anionic complex
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$r = \frac{{ - d\left[ A \right]}}{{dt}} = K\,{\left[ A \right]^{\frac{1}{2}}}\,{\left[ B \right]^{\frac{1}{2}}}\,{\left[ C \right]^{\frac{1}{4}}}$
The order of reaction is
$\mathrm{Eu}, \mathrm{Cm}, \mathrm{Er}, \mathrm{Tb}, \mathrm{Yb}$ and $\mathrm{Lu}$
(Molar mass $= 98\,g\,mol^{-1}$ ) by mass will be