

${C_6}{H_5} - N{O_2} + 6[H] \to {C_6}{H_5} - N{H_2} + 2{H_2}O$
The reducing agent used in this reaction is …….

$[P]\xrightarrow{\begin{subarray}{l}
(i)\,NAN{O_2}/HCl,\,0 - {5^o}C \\
(ii)\,\beta - napthol/NaOH
\end{subarray} }Colored\,\,Solid$
$[P]\xrightarrow{{B{r_2}/{H_2}O}}{C_7}{H_6}NB{r_3}$
The compound $[P]$ is

${C_6}{H_5}N{H_2}\mathop {\xrightarrow{{NaN{O_2}/HCl}}}\limits_{0 - 5\,^o C} X\mathop {\xrightarrow{{HN{O_2}}}}\limits_{C{H_2}O} Y + {N_2} + HCl$
$X$ and $Y$ are respectively