MCQ
In non – uniform circular motion, the resultant acceleration makes an angle with the radius vector is –
- ✓$\tan ^{-1}\left(\frac{r a_t}{v^2}\right)$
- B$\tan ^{-1}\left(\frac{a_t}{\left(\frac{r}{v^2}\right)}\right)$
- C$\tan ^{-1}\left(\frac{r v^2}{a t}\right)$
- D$\tan ^{-1}\left(\frac{r+a t^2}{v^2}\right)$