MCQ
In non – uniform circular motion, the resultant acceleration makes an angle with the radius vector is –
  • $\tan ^{-1}\left(\frac{r a_t}{v^2}\right)$
  • B
    $\tan ^{-1}\left(\frac{a_t}{\left(\frac{r}{v^2}\right)}\right)$
  • C
    $\tan ^{-1}\left(\frac{r v^2}{a t}\right)$
  • D
    $\tan ^{-1}\left(\frac{r+a t^2}{v^2}\right)$

Answer

Correct option: A.
$\tan ^{-1}\left(\frac{r a_t}{v^2}\right)$
$\tan ^{-1}\left(\frac{r a_t}{v^2}\right)$

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