MCQ
In oblique projection, maximum height attained by the projectile is –
- A$\frac{t}{u \cos \theta}$
- B$\frac{u \cos \theta}{2 g}$
- C$\frac{2 g}{u \cos \theta}$
- ✓$\frac{u^2 \sin ^2 \theta}{2 g}$
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