MCQ
In oblique projection, maximum height attained by the projectile is –
  • A
    $\frac{t}{u \cos \theta}$
  • B
    $\frac{u \cos \theta}{2 g}$
  • C
    $\frac{2 g}{u \cos \theta}$
  • $\frac{u^2 \sin ^2 \theta}{2 g}$

Answer

Correct option: D.
$\frac{u^2 \sin ^2 \theta}{2 g}$
$\frac{u^2 \sin ^2 \theta}{2 g}$

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