MCQ
In Quadrilateral $ABCD, \angle\text{A} = (3\text{x})^\circ, \ \angle\text{B} = (5\text{x})^\circ,\ \angle\text{C} = (20\text{x})^\circ,\ \angle\text{D} = (8\text{x})^\circ.$ Find the value of $x?$
- A$11$
- ✓$10$
- C$20$
- D$9$
$\angle\text{A} + \angle\text{B} + \angle\text{C} + \angle\text{D} = 360 ($angle sum property$)$
$3x + 5x + 20x + 8x = 360$
$36x = 360$
$x = 10$
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