MCQ
In quadrilateral $ABCD$, if $\angle\text{A}= 60^\circ$ and $\angle\text{B}: \angle\text{C}: \angle\text{D} = 2:3:7,$ then $\angle\text{D}$ is:
- ✓$175^\circ$
- B$25^\circ$
- C$180^\circ$
- D$50^\circ$
In quadrilateral, the sum of the all four angles equal to $360^\circ .$
Let $\angle\text{B} = 2\text{x}, \ \angle\text{C} = 3\text{x}$ and $\angle\text{D} = 7\text{x}.$
$\angle\text{A} + \angle\text{B} + \angle\text{C} + \angle\text{D} = 360^\circ$
$60 + 2x + 3x + 7x = 360$
$12x = 300$
$x = 25$
So, $\angle\text{D} = 7\text{x} = 7 (25) = 175^\circ$
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