In TeCl_4, the central atom tellurium involves: - Vidyadip

MCQ

In $\ce{TeCl_4},$ the central atom tellurium involves:

A
$sp^3$ hybridisation
✓
$\ce{sp^3d}$ hybridisation
C
$\ce{dsp^2}$ hybridisation
D
$\ce{sp^3d^2}$ hybridisation

✓

Answer

Correct option: B.

$\ce{sp^3d}$ hybridisation

Number of hybrid orbitals $=\frac{1}{2} ($no. of electrons in valence shell of atom $+$ no. of monovalent atoms $-$ charge no cation $+$ charge on the anion$.)$
Number of hybride orbitals $=\frac{1}{2}(6+4+0+0) = 5$
Hence$, \ce{TeCl_4}$ shows $\ce{sp^3d}$ hybridisation.

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