Question
In terms of Charle's law explain why -273°C is the lowest possible temperature?

Answer

According to Charle's law, $\text{V}_\text{t}=\text{V}_0\Big[1+\frac{\text{t}}{273}\Big]$
At t = -273°C, $\text{V}_\text{t}=\text{V}_0\Big[1-\frac{273}{273}\Big]=0$
Thus, at -273°C, volume of a gas becomes zero and below this temperature the volume becomes negative, which is meaningless.

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