MCQ
In the above reaction maximum Saytzeff product will be obtained, when $X$ is


- ✓$—I$
- B$—Cl$
- C$—Br$
- D$—F$

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$\mathrm{C}_{7} \mathrm{H}_{8} \stackrel{3 \mathrm{Cl}_{2} / \Delta}{\longrightarrow} \mathrm{A} \stackrel{\mathrm{Br}_{2} / \mathrm{Fe}}{\rightarrow} \mathrm{B} \stackrel{\mathrm{Zn} / \mathrm{HCl}}{\rightarrow} \mathrm{C}$
The product '$C$' is
(image) $\xrightarrow{{NBS}}\,\,\xrightarrow[{ether}]{{Mg}}\,\xrightarrow[{2.{H^ + }}]{{1.C{O_2}}}\,X$
The two products formed in above reaction are -