MCQ
In the above reaction $o/p$ ratio will be highest when


- ✓$R = - CH_3$
- B$R = - CH_2 -CH_3$
- C$R = - CHMe_2$
- D$R = - CMe_3$

Increase in size of $Y$ $\begin{gathered}
\downarrow \hfill \\
\downarrow \hfill \\
\downarrow \hfill \\
\downarrow \hfill \\
\downarrow \hfill \\
\end{gathered} $ $\begin{array}{*{20}{c}}
Y&{\% \,\,o - }&{\% \,p\, - } \\
{C{H_3}}&{58}&{37} \\
{C{H_2}Me}&{45}&{49} \\
{CHM{e_2}}&{30}&{62} \\
{CM{e_3}}&{16}&{73}
\end{array}$
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