MCQ
In the adjoining figure, $AB = AC$ and $\text{AD}\bot\text{BC}.$ The rule by which $\triangle\text{ABD}\cong\triangle\text{ACD}$ is:
- A$SAS$
- B$ASA$
- C$SSS$
- ✓$RHS$
✓
Answer
Correct option: D.
$RHS$
In $\triangle\text{ABD}$ and $\triangle\text{ACD},$ we have
$\angle\text{ADB} = \angle\text{ADC}$ (Right angles)
$AB = AC$ (Given and hypotenuses)
$AD = AD$ (common in both)
Therefore, $\triangle\text{ABD}\cong\triangle\text{ACD}$ by $RHS.$
$\angle\text{ADB} = \angle\text{ADC}$ (Right angles)
$AB = AC$ (Given and hypotenuses)
$AD = AD$ (common in both)
Therefore, $\triangle\text{ABD}\cong\triangle\text{ACD}$ by $RHS.$
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