MCQ
In the adjoining figure, $AB = BC$ and $\angle\text{ABD} = \angle\text{CBD},$ then another angle which measures $30^\circ $ is:
  • A
    $\angle\text{BAD}$
  • B
    $\angle\text{BCA}$
  • $\angle\text{BDA}$
  • D
    $\angle\text{BCD}$

Answer

Correct option: C.
$\angle\text{BDA}$
In triangle $ABD$ and $CBD$
$AB = BC$ and $\angle\text{ABD} = \angle\text{CBD},$ (Given)
$BD$ (Common)
Therefore In triangle $ABD$ and $CBD$ are congruent by $SAS$ criteria.
Therefore, $\angle\text{BDA}=30^\circ$ (by $CPCT)$

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