MCQ
In the adjoining figure, $ABCD$ is a quadrilateral in which $AD = CB$ and $AB = CD$, then $\angle\text{ACB}$ is equal to:

- ✓$\angle\text{CAD}$
- B$\angle\text{BAD}$
- C$\angle\text{BAC}$
- D$\angle\text{ACD}$

As $AB = CD,$
so, $\angle\text{ACB}=\angle\text{CAD}$ (alternate angles).
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