MCQ
In the adjoining figure, if $AC = AD$, then
- A$AB = AD$
- B$AB < AD$
- ✓$AB > AD$
- D$AB ≤ AD$
✓
Answer
Correct option: C.
$AB > AD$
$\angle\text{D} = \angle\text{C}$ (As $AC = AD)$
and $\angle\text{C} = \angle\text{B}$ and $\angle\text{D} = \angle\text{B}$
Hence, $AB > AD$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The consecutive sides of a quadrilateral have:
The marks obtained by $17$ students in a mathematics test (out of $100$) are given below: $91, 82, 100, 100, 96, 65, 82, 76, 79, 90, 46, 64, 72, 68, 66, 48, 49$. Find the range of the data.
→In the given figure, $\triangle\text{ABC}$ and $\triangle\text{DBC}$ are inscribed in a circle such that $\angle\text{BAC}=60^\circ$ and $\angle\text{DBC}=50^\circ.$ Then $\angle\text{BCD}=?$
→$\big(6+\sqrt{27}\big)-\big(3+\sqrt{3}\big)+\big(1-2\sqrt{3}\big)$ when simplified is:
→In Fig. if $\text {DC}\parallel\text{DC}$ and $\text{AB}=\text{AC},$ the value of $\angle\text{ABD}$ is:
→The figure shows two circles which intersect at $A$ and $B.$ The centre of the smaller circle is $O$ and it lies on the circumference of the larger circle. If $\angle\text{APB}=70^\circ,$ then the measure of $\angle\text{AGB}$ is: 
→$ABC$ is an isosceles triangle such that $AB = AC$ and $AD$ is the median to base $BC$. Then, $\angle\text{BAD} =$
→The bisects of exterior angles at $B$ and $C$ of $\triangle\text{ABC}$ meet at $O$. If $\angle\text{A}=\text{x}^\circ,$ then $\angle\text{BOC}=$
→If both $(x + 2)$ and $(2x + 1)$ are factors of $ax^2 + 2x + b$, than the value of $a - b$ is:
→In the given figure, $O$ is the centre of a circle and diameter $AB$ bisects the chord $CD$ at a point $E$ such that $CE = ED = 8\ cm$ and $EB = 4\ cm.$ The radius of the circle is:
→