MCQ
In the adjoining figure, $\triangle\text{ABC}\cong\triangle\text{ADC}.$ If $\angle\text{BAC} = 30^\circ$ and $\angle\text{ABC} = 100^\circ$ then $\angle\text{ACD}$ is equal to:
- A$80^{\circ}$
- B$60^{\circ}$
- C$30^{\circ}$
- ✓$50^{\circ}$
✓
Answer
Correct option: D.
$50^{\circ}$
In triangle ABC, $\angle\text{BAC} = 30^\circ$and $\angle\text{ABC} = 100^\circ$ (Given)$\angle\text{BAC} + \angle\text{ABC} + \angle\text{BCA} = 180^\circ$
$\angle\text{BAC} = 50^\circ$
Also $\angle\text{ACD} = 50^\circ$(Since, $\triangle\text{ABC}\cong\triangle\text{ADC}$)
$\angle\text{BAC} = 50^\circ$
Also $\angle\text{ACD} = 50^\circ$(Since, $\triangle\text{ABC}\cong\triangle\text{ADC}$)
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