MCQ
In the adjoining figure, $\triangle\text{ABG}\cong\triangle\text{ADG}.$ If $\angle\text{BAC} = 30^\circ$ and $\angle\text{ABC} = 100^\circ$ then $\angle\text{ACD}$ is equal to:
- ✓$50^\circ$
- B$80^\circ$
- C$30^\circ$
- D$60^\circ$
✓
Answer
Correct option: A.
$50^\circ$
In $\triangle\text{ABC}, \triangle\text{BAC} = 30^\circ$ and $\triangle\text{ABC}= 100^\circ$ (Given)
$\angle\text{BAC} + \angle\text{ABC}+ \angle\text{BCA} = 180^\circ$
$\angle\text{BCA}= 50^\circ$
Also $\angle\text{ACD}= 50^\circ$ (Since, $\triangle\text{ABC}\cong\triangle\text{ADC}$).
$\angle\text{BAC} + \angle\text{ABC}+ \angle\text{BCA} = 180^\circ$
$\angle\text{BCA}= 50^\circ$
Also $\angle\text{ACD}= 50^\circ$ (Since, $\triangle\text{ABC}\cong\triangle\text{ADC}$).
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