MCQ
In the compound $C{H_2} = CH - C{H_2} - C{H_2} - C \equiv CH,$ the ${C_2} - {C_3}$ bond is of the type
- A$sp - s{p^2}$
- B$s{p^3} - s{p^3}$
- C$sp - s{p^3}$
- ✓$s{p^2} - s{p^3}$
✓
Answer
Correct option: D.
$s{p^2} - s{p^3}$
(d) $\mathop {C{H_2} = \mathop {C{H_{}}}\limits_{s{p^2}} - \mathop {C{H_2}}\limits_{s{p^3}} - C{H_2} - C \equiv CH}\limits_{{\rm{hybridised}}\,\,\,\,\,} $
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