MCQ
In the cubic close packing, this unit cell has:
  • A
    $4$ tetrahedral voids each of which is shared by four adjacent unit cells.
  • B
    $4$ tetrahedral voids within the unit cell.
  • C
    $8$ tetrahedral voids each of which is shared by four adjacent unit cell.
  • $8$ tetrahedral voids within the unit cells.

Answer

Correct option: D.
$8$ tetrahedral voids within the unit cells.
Since, cube close packing is analogous to face$-$centered cubic $(\text{fcc})$ structure and number of atoms in a $\text{fcc}$ crystal is $4$ per unit cell.
So, number of tetrahedral voids $= 2\times$ Number of atoms in unit cell
$= 2 \times 4 = 8$

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