d
(d)
In given $V-I$ graph,
From $E$ to $F$,
$V_0=I_0 R_0$
$\Rightarrow \quad \text { s lope }=R_0$
$\therefore \text { At } F, \text { resistance }=R_0=\frac{V_0}{I_0}$
From $F$ to $G$,
$V=V_0=$ constant
But current increases, so resistance must decreases.
At $G$, resistance $=\frac{R_0}{2}=\frac{V_0}{2 I_0}$.
From $G$ to $H$, current is constant but voltage increases, so resistance decreases.
At $H$, resistance $=\frac{2 V_0}{2 I_0}=\frac{V_0}{I_0}=R_0$
So, correct option is $(d)$.
