$-6+3 I_{1}+1\left(I_{i}-I_{2}\right)=0$

$6=3 \mathrm{I}_{1}+\mathrm{I}_{1}-\mathrm{I}_{2}$

$4 \mathrm{I}_{1}-\mathrm{I}_{2}=6$       .....$(1)$

$-9+2 I_{2}-\left(I_{1}-I_{2}\right)+3 I_{2}=0$

$-\mathrm{I}_{1}+6 \mathrm{I}_{2}=9$      ....$(2)$

On solving $( 1)$ and $( 2)$

$\mathrm{I}_{1}=0.13\, \mathrm{A}$

Direction $Q$ to $P,$ since $I_{1}>I_{2}$.