In the circuits shown below, the readings of the voltmeters and the ammeters will be
NEET 2019, Medium
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$10 \Omega$ is in series with ideal voltmeter. Therefore it will not affect the circuit
$\mathrm{I}_{1}=\frac{10}{10}=1 \;\mathrm{A}$
$\mathrm{I}_{2}=\frac{10}{10}=1\; \mathrm{A}$
$V_1=10\;V$
$V_{2}=10\;V$
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