In the electric network shown, when no current flows through the $4 \Omega$ resistor in the arm EB, the potential difference between the points $A$ and $D$ will be $.............\,V$
A$6$
B$3$
C$5$
D$4$
Medium
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C$5$
c (c)
As no current flows through arm $E B$ then $V _{ D }=0 V ; \quad V _{ E _{ D }}=0 V ; \quad V _{ B }=-4 V ; \quad V _{ A }=5 V$ So, potential difference between the points $A$ and $D$
$V_A-V_D=5\,V$
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