MCQ
In the electronic structure of acetic acid, there are
- ✓$16$ shared and $8$ unshared electrons
- B$8 $ shared and $16$ unshared electrons
- C$12$ shared and $12$ unshared electrons
- D$18$ shared and $6$ unshared electrons
✓
Answer
Correct option: A.
$16$ shared and $8$ unshared electrons
a
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The reactions of $Cl _2$ gas with cold-dilute and hot-concentrated $NaOH$ in water give sodium salts to two (different) oxoacids of chlorine, $P$ and $Q$, respectively. The $Cl _2$ gas reacts with $SO _2$ gas, in presence of charcoal, to give a product $R$. $R$ reacts with white phosphours to give a compound $S$. On hydrolysis, $S$ gives an oxoacid of phosphours $T$
→$1.$ $P$ and $Q$, respectively, are the sodium salts of
$(A)$ hypochlorus and chloric acids
$(B)$ hypochlorus and chlorus acids
$(C)$ chloric and perchloric acids
$(D)$ chloric and hypochlorus acids
$2.$ $R , S$ and $T$, respectively, are
$(A)$ $SO _2 Cl _2, PCl _5$ and $H _3 PO _4$
$(B)$ $SO _2 Cl _2, PCl _3$ and $H _3 PO _3$
$(C)$ $SOCl _2, PCl _3$ and $H _3 PO _2$
$(D)$ $SOCl _2, PCl _5$ and $H _3 PO _4$
Give the answer question $1$ and $2.$
$K_p$ for the following reaction at $700\, K$ is $1.3 \times {10^{ - 3}}$ $atm$$^{-1}$. The $ K_c$ at same temperature for the reaction $2S{O_2} + {O_2} $ $\rightleftharpoons$ $ 2S{O_3}$ will be
→For which of the following reaction $\Delta \,H^o$ value is equal to the first ionization energy of $Ca$ is ?
→The major products $A$ and $B$ from the following reactions are:
→Match List-$I$ with List-$II$.
→Choose the correct answer from the options given below:
The first ionization energy of boron is less than that of beryllium because
Which one of the following statement is true for a electrochemical cell
Metal used for making joints in jewellery is
At $90\,^oC$ , pure water has $[H^+] = 10^{-6}\,M$ , if $100\, mL$ of $0.2\, M\, HCl$ is added to $200\, mL$ of $0.1\, M\, KOH$ at $90\,^oC$ then $pH$ of the resulting solution will be
→(image) $\xrightarrow[{CC{l_4}}]{{{\text{B}}{{\text{r}}_2}}}\,(X){\kern 1pt}$ products. Value of $X$ is
→