In the experiment to determine the galvanometer resistance by hal… - Vidyadip

Question

In the experiment to determine the galvanometer resistance by half $-$ deflection method, the plot of $\frac{1}{\theta}$ vs the resistance $(R)$ of the resistance box is shown in the figure. The figure of merit of the galvanometer is $........ \times 10^{-1} A$ division. $[$The source has emf $2V]$

✓

Answer

$(c)\ (5)$
$i=K \theta$
$\frac{2}{G+R}=K \theta$
$\Rightarrow \frac{1}{\theta}=\frac{(G+R) K}{2}$
$=R\left(\frac{K}{2}\right)+\frac{K G}{2}$
Slope $=\frac{K}{2}=\frac{1}{4} $
$\Rightarrow K=0.5$
$=5 \times 10^{-1} A$

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