Understanding Shapes – II (Special Types of Quadrilaterals) — MATHS STD 8 — Question
Gujarat BoardEnglish MediumSTD 8MATHSUnderstanding Shapes – II (Special Types of Quadrilaterals)3 Marks
Question
In the figure, $BDEF$ and $DCEF$ are each a parallelogram. It is true that $BD = DC?$ Why or why not$?$
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Answer
In parallelogram $BDEF, BD = EF ……(i) ($Opposite sides of a parallelogram$)$
Similarly, in parallelogram $DCEF$
$DC = EF$ From $(i)$ and $(ii)$
$BD = DC$
Hence it is true that $BD = DC.$
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