Question
In the figure given alongside, find the measure of $\angle\text{ACD}.$
✓
Answer
In $\triangle\text{ABC},$
$\angle\text{A}=75^\circ,\angle\text{B}=45^\circ$
side BC is produced to D
Forming exterior $\angle\text{ACD}$
Exterior $\angle\text{ACD}=\angle\text{A}+\angle\text{B}$ (Exterior angle is equal to sum of its interior opposite angles)
= 75° + 45° = 120°
$\angle\text{A}=75^\circ,\angle\text{B}=45^\circ$
side BC is produced to D
Forming exterior $\angle\text{ACD}$
Exterior $\angle\text{ACD}=\angle\text{A}+\angle\text{B}$ (Exterior angle is equal to sum of its interior opposite angles)
= 75° + 45° = 120°
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