Question
In the figure given below, a line segment is drawn parallel to one side of the triangle and the lengths of certain line-segment are marked. Find the value of x in the following:

Answer



In the figure
$DE\ ||\ CA$
$\therefore\frac{\text{BD}}{\text{DC}}=\frac{\text{BE}}{\text{EA}}$
$\Rightarrow\frac{1}{\text{g}}=\frac{\text{g}}{\text{x}}\Rightarrow\text{x}=\text{g}^2$
Hence $x = g^2$

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