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Circles — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsCircles1 Mark
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Answer

  1. 70º
    Solution:

    In, $\triangle\text{ABD}$
    $\angle\text{D}=180^\circ-\angle\text{A}-\angle\text{B}$
    $=180^\circ-110^\circ=70^\circ$
    Since angles made by same chord at any point of circumference are equal so,
    $\angle\text{ACB}=\angle\text{ADB}=70^\circ$

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