In the figure, if $\angle\text{AOB}=125^\circ$ then $\angle\text{COD}$ is equal to:
A
45°
B
35°
✓
55°
D
$62\frac{1}{2}^\circ$
✓
Answer
Correct option: C.
55°
We know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle
$\angle\text{AOB}+\angle\text{COD}=180^\circ$
$\Rightarrow\angle\text{COD}=180^\circ-\angle\text{AOB}=180^\circ-125^\circ=55^\circ$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
