MCQ
In the figure, if $\angle\text{DAB}=60^\circ,\angle\text{ABD}=50^\circ$ then $\angle\text{ACB}$ is equal to:
- A$80^\circ$
- B$60^\circ$
- C$50^\circ$
- ✓$70^\circ$
✓
Answer
Correct option: D.
$70^\circ$
In, $\triangle\text{ABD}$
$\angle\text{D}=180^\circ-\angle\text{A}-\angle\text{B}$
$=180^\circ-110^\circ=70^\circ$
Since angles made by same chord at any point of circumference are equal so,
$\angle\text{ACB}=\angle\text{ADB}=70^\circ$
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