In the figure shown a mass $1\ kg$ is connected to a string of mass per unit length $1.2\ gm/m$ . Length of string is $1\ m$ and its other end is connected to the top of a ceiling which is accelerating up with an acceleration $2\ m/s^2$ . A transverse pulse is produced at the lowest point of string. Time taken by pulse to reach the top of string is .... $s$
Diffcult
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$\mathrm{v}=\sqrt{\frac{\mathrm{T}}{\mu}}=\sqrt{\frac{\mathrm{Mg}_{\mathrm{eff}}}{\mu}}$
$=\sqrt{\frac{(1)(\mathrm{g}+\mathrm{a})}{\mu}}=\sqrt{\frac{12}{1.2 \times 10^{-3}}}$
$=100 \mathrm{\,m} / \mathrm{s}$
${\rm{t}} = \frac{l}{{\rm{v}}} = \frac{1}{{100}} = 0.01\,{\rm{s}}$
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