In the figure shown, the effective capacitance between the points $A$ and $B$, if each has capacitance $C$, is
A$2\,C$
B$\frac{C}{5}$
C$5\,C$
D$\frac{C}{2}$
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A$2\,C$
a (a) The given circuit can be simplified as follows
Equivalent capacitance between $A$ and $B$ is $C_{AB} = 2 \,C$
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