MCQ
In the following circuit, $18\,\Omega $ resistor develops $2\,J/sec$ due to current flowing through it. The power developed across $10\,\Omega $ resistance is .............. $W$
- A$125$
- ✓$10$
- C$0.8$
- D$25$
✓
Answer
Correct option: B.
$10$
b
The given circuit can be redrawn as follows
The given circuit can be redrawn as follows
$\frac{{{i_1}}}{{{i_2}}} = \frac{9}{{18}} = \frac{1}{2}$
and $i = {i_1} + {i_2}$
$ \Rightarrow \frac{i}{{{i_1}}} = 1 + \frac{{{i_2}}}{{{i_1}}} = 1 + 2 = 3$
From $P = {i^2}R \Rightarrow \frac{{{P_{10\,\Omega }}}}{{{P_{18\,\Omega }}}} = {\left( {\frac{i}{{{i_1}}}} \right)^2} \times \frac{{10}}{{18}}$ $ \Rightarrow {P_{10\,\Omega }}\, = 10\,W$
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