
$\frac{x-(y+5)}{1}+\frac{x-2}{2}+\frac{x-0}{2}=0$
Junction law at $B$,
$\frac{y+5-x}{1}+\frac{y-0}{1}+\frac{y-2}{1}=0$
On solving equation (1) and Equation (2) $x =3$
$y=0$
At $D$ junction
$I_1 =i_1+i_2$
$I_1 =\frac{y-0}{1}+\frac{x-0}{2}$
$=\frac{0-0}{1}+\frac{3-0}{2}$
$I_1 =1.5\,A$
$[1]$ battery emf is increased
$[2]$ all resistances are increased by $10\,ohms$
$[3]$ all resistances are made five times
$[4]$ the battery and the galvanometer are interchanged


