Question
In the following, determine whether the given values are solution of the given equation or not:
$x^2 + x + 1 = 0, x = 0, x = 1$

Answer

We have been given that,
$x^2 + x + 1 = 0, x = 0, x = 1$
Now, if $x = 0$ is a solution of the equation then it should satisfy the equation.
So, substituting $x = 0$ in the equation we get
$x^2 + x + 1$
$= (0)^2 + (0) + 1$
$= 1$
Hence $x = 0$ is not a solution of the given quadratic equation.
Also, if $x = 1$ is a solution of the equation it should satisfy the equation So, substituting $x = 1$ in the equation, we get
$x^2 + x + 1$
$= (1)^2 + (1) + 1$
$= 3$
Hence $x = 1$ is not a soluion of the quadratic equation.
Therefore, from the above results we find out that both $x = 0$ and $x = 1$ are not a solution of the given quadratic equation.

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