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Quadratic Equations — Maths STD 10 — Question

Maharashtra BoardEnglish MediumSTD 10MathsQuadratic Equations4 Marks
Question
In the following, determine whether the given values are solution of the given equation or not:
$\text{x}+\frac{1}{\text{x}}=\frac{13}{6},$ $\text{x}=\frac{5}{6},\text{x}=\frac{4}{3}$
✓

Answer

$\text{x}+\frac{1}{\text{x}}=\frac{13}{6},$ $\text{x}=\frac{5}{6},\text{x}=\frac{4}{3}$When, $\text{x}=\frac{5}{6}$
Substituting $\text{x}=\frac{5}{6}$
L.H.S.
$=\frac{5}{6}+\frac{6}{5}$
$=\frac{25+36}{30}$
$=\frac{61}{30}\neq\frac{13}{6}$
$\therefore\text{x}=\frac{5}{6}$ is not its solution
When, $\text{x}=\frac{4}{3}$
Substituting $\text{x}=\frac{4}{3}$
L.H.S.
$=\text{x}+\frac{1}{\text{x}}=\frac{4}{3}+\frac{3}{4}$
$=\frac{16+9}{12}$
$=\frac{25}{12}\neq\frac{13}{6}$
$\therefore\text{x}=\frac{4}{3}$ is not its solution.

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