In the following diagram the wheat stone bridge is balanced when we interchange the resistances of
Medium
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Current density in a cylindrical wire of radius $R$ is given as $J =$ $\left\{ {\begin{array}{*{20}{c}}
{{J_0}\left( {\frac{x}{R} - 1} \right)\,\,for\,\,0 \leqslant x < \frac{R}{2}} \\
{{J_0}\frac{x}{R}\,\,\,\,for\,\,\,\frac{R}{2} \leqslant x \leqslant R}
\end{array}} \right.$The current flowing in the wire is:
Two heaters $A$ and $B$ have power rating of $1 \mathrm{~kW}$ and $2 \mathrm{~kW}$, respectively. Those two are first connected in series and then in parallel to a fixed power source. The ratio of power outputs for these two cases is:
The $V-i$ graph for a conductor makes an angle $\theta $ with $V-$ axis. Here $ V$ denotes the voltage and $i$ denotes current. The resistance of conductor is given by
A copper wire of length $1\, m$ and radius $1\, mm$ is joined in series with an iron wire of length $2\, m$ and radius $3\, mm$ and a current is passed through the wires. The ratio of the current density in the copper and iron wires is
In the electric network shown, when no current flows through the $4 \Omega$ resistor in the arm EB, the potential difference between the points $A$ and $D$ will be $.............\,V$