In the following figure, O is centre of the circle and ΔABC is equilateral. Find:(i) ∠ADB, (ii) ∠AEB.
Exercise 17 (A) | Q 11 | Page 258
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Since ∠ACBand ∠ADBare in the same segment, ∠ADB = ∠ACB = 60° Join OA and OB Here, ∠AOB =2 ∠ACB = 2×60° = 120° $\angle A E B=\frac{1}{2} \operatorname{Reflex}(\angle AOB )=\frac{1}{2}\left(360^{\circ}-120^{\circ}\right) 120^{\circ}$ (Angle at the centre is double the angle at the circumference subtended by the same chord)
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The figure given below, shows a circle with centre O. Given: ∠ AOC = a and ∠ ABC = b.
1. Find the relationship between a and b.
2. Find the measure of angle OAB, if OABC is a parallelogram.
In the given figure, AB is a side of a regular six-sided polygon and AC is a side of a regular eight sided polygon inscribed in the circle with centre O. Calculate the sizes of:
(i) ∠AOB, (ii) ∠ACB (iii) ∠ABC
In the figure, AB is a common chord of the two circles. If AC and AD are diameters; prove that D, B, and C are in a straight line. $O_1$ and $O_2$ are the centers of two circles.