MCQ
- A$0.8 A$
- B$1.0 A$
- ✓$1.2 A$
- D$1.4 A$
✓
Answer
Correct option: C.
$1.2 A$
(c) : Since the network forms a wheatstone bridge
$
\frac{R_{A B}}{R_{A D}}=\frac{R_{B C}}{R_{C D}} \Rightarrow \frac{15}{20}=\frac{3}{4}
$
Hence, simplified circuit will be
$
\begin{aligned}
& I_1+I_2=2.1 A \\
& \quad 18 I_1=24 I_2 \\
& \Rightarrow \quad 3 I_1=4 I_2=4\left(2.1-I_1\right)
\end{aligned}
$
$\Rightarrow \quad 7 I_1=8.4 \Rightarrow I_1=\frac{8.4}{7}=1.2 A$
$
\frac{R_{A B}}{R_{A D}}=\frac{R_{B C}}{R_{C D}} \Rightarrow \frac{15}{20}=\frac{3}{4}
$
Hence, simplified circuit will be
$
\begin{aligned}
& I_1+I_2=2.1 A \\
& \quad 18 I_1=24 I_2 \\
& \Rightarrow \quad 3 I_1=4 I_2=4\left(2.1-I_1\right)
\end{aligned}
$
$\Rightarrow \quad 7 I_1=8.4 \Rightarrow I_1=\frac{8.4}{7}=1.2 A$
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