Question
In the following reaction between lead sulphide and hydrogen peroxide:
$\text{PbS}(\text{s})\ +\ 4\text{H}_2\text{O}_2(\text{aq})\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ }\text{PbSO}_4(\text{s})\ +\ \text{4H}_2\text{O}(\text{l})$
$\text{PbS}(\text{s})\ +\ 4\text{H}_2\text{O}_2(\text{aq})\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ }\text{PbSO}_4(\text{s})\ +\ \text{4H}_2\text{O}(\text{l})$
- Which substance is reduced?
- Which substance is oxidised?