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STD 12 - 7. Alcohol, phenol and ethers — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 7. Alcohol, phenol and ethers4 Marks
MCQ
In the following reaction, final product is
  • A
    $\begin{array}{*{20}{c}}
      {ClC{H_2}CH\mathop C\limits^{14} {H_2}O{C_2}{H_5}} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}$
  • B
    $\begin{array}{*{20}{c}}
      {ClC{H_2}CH\mathop C\limits^{14} {H_2}ONa} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {O{C_2}{H_5}} 
    \end{array}$
  • C

  • ✓

✓

Answer

Correct option: D.

d
Three membered epoxide ring has ring strain. So, on reaction with nucleophile $\left( C _2 H _5 O ^{\ominus}\right)$ on less hindered carbon. It cleave epoxide ring and then negative oxygen atom attack to substitute chlorine because chlorine is good leaving group.

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