MCQ
In the following the correct bond order sequence is :
  • $\mathrm{O}_{2}^{+}>\mathrm{O}_{2}>\mathrm{O}_{2}^{-}>\mathrm{O}_{2}^{2-}$
  • B
    $\mathrm{O}_{2}>\mathrm{O}_{2}^{-}>\mathrm{O}_{2}^{2-}>\mathrm{O}_{2}^{+}$
  • C
    $\mathrm{O}_{2}^{2-}>\mathrm{O}_{2}^{+}>\mathrm{O}_{2}^{-}>\mathrm{O}_{2}$
  • D
    $\mathrm{O}_{2}^{+}>\mathrm{O}_{2}^{-}>\mathrm{O}_{2}^{2-}>\mathrm{O}_{2}$

Answer

Correct option: A.
$\mathrm{O}_{2}^{+}>\mathrm{O}_{2}>\mathrm{O}_{2}^{-}>\mathrm{O}_{2}^{2-}$
a
$\sigma_{1 s}^{2}, \sigma_{1 s}^{* 2}, \sigma_{2 s}^{2}, \sigma_{2 s}^{*}, \sigma_{2 p_{2}}^{2}$

$\pi_{2 p_{x}}^{2}=\pi_{2 p_{y}}^{2}, \pi_{2 p_{x}}^{*_{1}}=\pi_{2 p_{y}}^{*_{1}}, \sigma_{2 p_{2}}^{*}$

Bond order of $\mathrm{O}_{2} \Rightarrow 2$

Bond order of $\mathrm{O}_{2}^{-} \Rightarrow 1.5$

Bond order of $\mathrm{O}_{2}^{2-} \Rightarrow 1$

Bond order of $\mathrm{O}_{2}^{+} \Rightarrow 2.5$

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