MCQ
In the given circuit, the current $(I)$ through the battery will be $..........\,A$


- ✓$1.5$
- B$1$
- C$2.5$
- D$2$

$\therefore I =\frac{10}{20 / 3}=\frac{3}{2}\,A =1.5\,A$
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Where $h =$ Planck's constant, $m =$ mass of electron and $c =$ speed of light.