In the given circuit, with steady current, the potential drop across the capacitor must be
IIT 2001, Diffcult
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(c) Moving anticlockwise from $A$
$ - \,iR - V + 2V - 2iR = 0$
or $3iR = V$ or $i = \frac{V}{{3R}}$
${V_A} - {V_B} = iR + V - V = iR$
$==>$ Potential drop across $C$ =$\frac{V}{3}$
$ - \,iR - V + 2V - 2iR = 0$
or $3iR = V$ or $i = \frac{V}{{3R}}$
${V_A} - {V_B} = iR + V - V = iR$
$==>$ Potential drop across $C$ =$\frac{V}{3}$
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