Question
✓
Answer
- 50º
Solution:
$\angle\text{APQ}=\angle\text{PQR}=70^\circ$ (Alternate interior angles)
$\angle\text{PRQ}+\angle\text{PRD}=180^\circ$ (Linear Pair)
$\angle\text{PRQ}=180^\circ-120^\circ=60^\circ$
In $\triangle\text{PQR}$
$\angle\text{PQR}+\angle\text{PRQ}+\angle\text{QPR}=180^\circ$ (Angle sum property)
$\angle\text{QPR}=180^\circ-70^\circ-60^\circ=50^\circ.$
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