Answer

  1. 55º
    Solution:
    $\angle\text{BAF}=\angle\text{DCF}=80^\circ$ (Corresponding angle)
    In $\triangle\text{CEF}$
    $\angle\text{CFE}+\angle\text{CEF}=\angle\text{DCF}$ (exterior angle is equal to the sum of its two opposite interior angles)
    $25^\circ+\angle\text{CEF}=80^\circ$
    $\angle\text{CEF}=55^\circ$

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